import uuid
import time


d = dict()
n = 0
for i in range(1000000):
    now_time = str(time.time())
    id = str(uuid.uuid4())[:6]+now_time
    if id in d:
        print(id)
        n += 1
    else:
        d[id] = 1
print(id)
print(f'总共有 {n} 个重复的 uuid')